a. a = (Vf - Vo) / t,
a = (8.86 _ 0) / 3.3 = 2.68m/s^2.
b. d = Vo + 0.5a*t^2,
d = 0 + 1.34*(3.3)^2 = 14.62m.
a = (8.86 _ 0) / 3.3 = 2.68m/s^2.
b. d = Vo + 0.5a*t^2,
d = 0 + 1.34*(3.3)^2 = 14.62m.
Average acceleration = (final velocity - initial velocity) / time
In this case, the skier starts from rest, so the initial velocity (u) is 0 m/s. The final velocity (v) is 8.86 m/s, and the time (t) is 3.30 s.
(a) To find the magnitude of the average acceleration:
Average acceleration = (8.86 m/s - 0 m/s) / 3.30 s = 2.68 m/s^2
So, the magnitude of the average acceleration of the skier is 2.68 m/s^2.
To find how far the skier travels in this time, we can use the equation for distance traveled:
Distance = (initial velocity + final velocity) / 2 * time
In this case, the initial velocity (u) is 0 m/s, the final velocity (v) is 8.86 m/s, and the time (t) is 3.30 s.
(b) To find the distance traveled:
Distance = (0 m/s + 8.86 m/s) / 2 * 3.30 s = 14.58 m
So, the skier travels a distance of 14.58 meters in 3.30 seconds.