Asked by Bridgette

A rocket is launched at an angle of ascent (elevation) of 18 degrees. When it has traveled 6000 ft, what is its height above the ground?
Answered by Anonymous
L = traveled way

H = Height


sin ( 18° ) = H / L

sin ( 18° ) = H / 6000

H = 6000 sin ( 18° )

H = 6000 0.30902

H = 1854.12 ft
Answered by tchrwill
There is insufficient information to determine the height after traveling 6000 ft. horizontally. It will definitely be on an angle less than 18º from the launch point.
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