A rocket is launched at an angle of ascent (elevation) of 18 degrees. When it has traveled 6000 ft, what is its height above the ground?

Answer 1

L = traveled way

H = Height

sin ( 18° ) = H / L

sin ( 18° ) = H / 6000

H = 6000 sin ( 18° )

H = 6000 0.30902

H = 1854.12 ft

Answer 2

There is insufficient information to determine the height after traveling 6000 ft. horizontally. It will definitely be on an angle less than 18º from the launch point.