Asked by Anil

why are these equations poor models of hitting a baseball:

y= -0.002x(x-433.1)

I get maximums of (216,93). Other problems' maximums are in the (220, 100)range. So are they poor models because the distance and heights are unreasonable?

2) Why is the constant a in y=ax^2 + bx + c negative in a reasonable model?
is it because the graph is then a hill versus a valley?

Answers

Answered by Steve
1. Plenty of players hit the ball 400 feet or more. This function has roots at 0,433, so it appears to model typical hitting ability.

2. negative a means that there is a downward force acting on the ball: gravity. so, yes, the graph is a hill. The ball takes off at some speed, but gravity slows down its ascent and makes it drop back to earth.
Answered by Damon
y= -0.002x(x-433.1)
is
y = .8662 x - .002 x^2
I do not see anything very wrong except that the baseball does not start out at zero height. When x = 0 y should be like one meter high so I might prefer something like
y = 1 + .8662 x - .002 x^2

Yes, coef of x^2 must be negative because as x gets big the ball must drop.
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