Asked by simantha
Vector is 6.3 units long and points along the negative axis. Vector is 9.0 units long and points at 55 to the positive axis.
1- What are the and components of vector ?
2-What are the and components of vector ?
3-Determine the magnitude of the sum .
4-Determine the angle of the sum .
i've tried to solve it but i don't really get it.. im stuck
1- What are the and components of vector ?
2-What are the and components of vector ?
3-Determine the magnitude of the sum .
4-Determine the angle of the sum .
i've tried to solve it but i don't really get it.. im stuck
Answers
Answered by
Henry
1. V1 = (6.3,180deg).
X1 = hor. = 6.3cos180 = -6.3 Units.
Y1 = ver. = 6.3sin180 = 0 Units
2. V2 = (9,55deg.).
X2 = hor. = 9cos55 = 5.16 Units.
Y2 = ver. = 9sin55 = 7.37 Units.
3.Sum = (X!+X2) + i(Y1+Y2),
Sum = (-6.3+5.16) + i(0+7.37),
Sum = -1.14 + i7.37.
Sum = sqrt((-1.14)^2 + (7.37)^2) = 7.46 Units.
4. tanA = Y/X=7.37 / -1.14 = -6.4649
A = -81.2 deg.,CW.
A = -81.2 + 180 = 98.8 deg.,CCW.
X1 = hor. = 6.3cos180 = -6.3 Units.
Y1 = ver. = 6.3sin180 = 0 Units
2. V2 = (9,55deg.).
X2 = hor. = 9cos55 = 5.16 Units.
Y2 = ver. = 9sin55 = 7.37 Units.
3.Sum = (X!+X2) + i(Y1+Y2),
Sum = (-6.3+5.16) + i(0+7.37),
Sum = -1.14 + i7.37.
Sum = sqrt((-1.14)^2 + (7.37)^2) = 7.46 Units.
4. tanA = Y/X=7.37 / -1.14 = -6.4649
A = -81.2 deg.,CW.
A = -81.2 + 180 = 98.8 deg.,CCW.
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