Asked by sara
Two cyclists, 36 miles apart, start riding toward each other at the same time. One cycles 2 times as fast as the other. If they meet 2 hours later, what is the speed (in mi/h) of the faster cyclist?
Answers
Answered by
Steve
Both riders ride for 2 hours
add up their distances to be 36
distance = speed*time
2s + 2*2s = 36
6s=36
s=6
slow rider rides 2hrs*6mph = 12 mi
fast rider rides 2hrs*12mph = 24mi
add up their distances to be 36
distance = speed*time
2s + 2*2s = 36
6s=36
s=6
slow rider rides 2hrs*6mph = 12 mi
fast rider rides 2hrs*12mph = 24mi
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