Ask a New Question
Menu

Suppose that 50 mL of 0.3 M LiOH and 60 mL of 0.1 M NaHSO3 are mixed.

What is the K for the dominant equilibrium in terms of Ka's, Kb's, Kw etc.?

Ka of HSO3-
1/Ka of HSO3-
Kb of OH-
1/Kb of OH-
Kb of SO3-2
1/Kb of SO3-2
Kw
1/Kw
There is no reaction.

1 answer

LiOH + NaHSO3 ==> H2O + NaLiSO3

You have 50*0.3 = 15 mmoles LiOH
You have 50*0.1 = 5 mmoles NaHSO3
So you have 10 mmoles LiOH in excess (which is a strong base) with all of the NaHSO3 reacted. Thus the dominant equilibrium, as I see it, is the strong base of LiOH.
Similar Questions
    1. answers icon 3 answers
  2. 1.)KMnO4+H2SO4+NaHSO3-->2.)KMnO4+NaOH+NaHSO3--> 3.)KMnO4+NaHSO3----> Write the net ionic equations for the reactions
    1. answers icon 2 answers
  3. This is what i did thus farI wrote the eqn and i sed 1 mole of LiOH = 24g x mole = 1 g cross multiply the # of moles = 0.042mol
    1. answers icon 0 answers
  4. Which response includes all of the followingLiOH, KOH, Ni(OH)2, Mg(OH)2, Ca(OH)2 that are insoluble bases, and no others? 1.
    1. answers icon 2 answers
more similar questions