Asked by Katie A
(3x^2y-^5)-^3
What????
What????
Answers
Answered by
Steve
(3x²y⁻⁵)⁻³
= (3x²/y⁵)⁻³
= (y⁵/3x²)³
= y¹⁵/27x⁹
= (3x²/y⁵)⁻³
= (y⁵/3x²)³
= y¹⁵/27x⁹
Answered by
Steve
Rats that would be
y¹⁵/27x⁶
y¹⁵/27x⁶
Answered by
Katie A
what are these squares in the answer? I am lost
Answered by
Steve
Ahh. Apparently a font difference between your browser and mine. Let me rephrase:
(3x^2 y^-5)^-3
= (3x^2/y5)^-3
= (y^5/3x^2)^3
= y^15/27x^6
(3x^2 y^-5)^-3
= (3x^2/y5)^-3
= (y^5/3x^2)^3
= y^15/27x^6
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