Asked by Becky
You are at isoelectric point for a solution of Leucine. If the number of negatively charged carboxyl ate groups, -COO-, is 1x10^19, how many positively charged amino groups, NH3+, would there be?
Answers
Answered by
DrBob222
Wouldn't that be 1 x 10^19 + charges so that the net charge would be zero?
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