To calculate the percent composition of calcium acetate (Ca(CH3COO)2), you need to determine the molar mass of each element in the compound.
1. Calcium (Ca):
- Atomic mass of calcium (Ca) = 40.08 g/mol
2. Carbon (C):
- Atomic mass of carbon (C) = 12.01 g/mol
- Since there are two carbon atoms in calcium acetate, the total mass of carbon = 2 * 12.01 g/mol = 24.02 g/mol
3. Hydrogen (H):
- Atomic mass of hydrogen (H) = 1.01 g/mol
- Since there are four hydrogen atoms in calcium acetate, the total mass of hydrogen = 4 * 1.01 g/mol = 4.04 g/mol
4. Oxygen (O):
- Atomic mass of oxygen (O) = 16.00 g/mol
- Since there has four oxygen atoms in calcium acetate, the total mass of oxygen = 4 * 16.00 g/mol = 64.00 g/mol
Now, let's calculate the total molar mass of calcium acetate:
Total molar mass = mass of calcium + mass of carbon + mass of hydrogen + mass of oxygen
= 40.08 g/mol + 24.02 g/mol + 4.04 g/mol + 64.00 g/mol
= 132.14 g/mol
To find the percent composition of calcium acetate:
1. Calcium:
Percent composition of calcium = (mass of calcium / total molar mass) x 100%
= (40.08 g/mol / 132.14 g/mol) x 100%
≈ 30.32%
2. Carbon:
Percent composition of carbon = (mass of carbon / total molar mass) x 100%
= (24.02 g/mol / 132.14 g/mol) x 100%
≈ 18.16%
3. Hydrogen:
Percent composition of hydrogen = (mass of hydrogen / total molar mass) x 100%
= (4.04 g/mol / 132.14 g/mol) x 100%
≈ 3.06%
4. Oxygen:
Percent composition of oxygen = (mass of oxygen / total molar mass) x 100%
= (64.00 g/mol / 132.14 g/mol) x 100%
≈ 48.45%
Therefore, the percent composition of calcium acetate is approximately:
- Calcium (Ca): 30.32%
- Carbon (C): 18.16%
- Hydrogen (H): 3.06%
- Oxygen (O): 48.45%