Question

What is the molarity of H2SO4 in a solution prepared by adding 15.0 mL of 6.0 Molarity H2S04 to enough water to make 100.0 mL of solution?
There are two easy ways to do this.
1. mL1 x M1 = mL2 x M2 and solve for the new molarity OR
2. 6.0 x (15.0/100.0) = ?
C1V1=C2V2
6*0.015=C2*0.1

..a bit of transposition
(0.015*6)/0.1=C2
C2= 0.9

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