work= change in KE= 1/2 m 10.6^2
There are harder ways.
find the acceleration: Vf^2=Vi^2+2ad solve for a
Then F=ma solve for force
work= force*distance.
The driver of a 1350 kg car, initially traveling at 10.6 m/s, applies the brakes, bringing the car to rest in a distance of 15.0 m.
Find the net work done on the car.
Not sure how to set this problem up.
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