Asked by Anonymous
Find the domain of 2x^3-5 divided by x^2+x-6
Answers
Answered by
Anonymous
Values of x where x^2+x-6 differently of zero.
x^2+x-6=0 for
x= -3
and
x= 2
Domain: (- infinity,-3]U[-3,2]U[2,infinity)
x^2+x-6=0 for
x= -3
and
x= 2
Domain: (- infinity,-3]U[-3,2]U[2,infinity)
Answered by
Reiny
since x^2 + x - 6 = (x+3)(x-2)
the functions has vertical asymptotes at x=-3 and x=2 , because we would be dividing by zero
domain: any real values of x , x≠-3,2
the functions has vertical asymptotes at x=-3 and x=2 , because we would be dividing by zero
domain: any real values of x , x≠-3,2
Answered by
Steve
The intervals need to be open on both ends, since the endpoints are not included
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.