Question

A mass of 18 kg is being pushed up a frictionless incline with a constant force of 20 Newtons directed parallel to the incline, up the incline. At the top of the incline the mass is moving at 23 m/s up the incline. If the angle of inclination is 58 degrees and the height (not length) of the incline is 24 meters, what was the magnitude of the mass's velocity at the bottom of the incline in m/s?

Answer 1

Vf^2 = Vo^2 + 2g*d,
Vo^2 = Vf^2 - 2g*d,
Vo^2 -= (23)^2 - (-19.6)*24 = 999.4
Vo = 3i.6m/s = Yo = ver. component of
initial velocity @ bottom of incline.

Vo = Yo / sinA = 31.6 / sin58=37.3m/s.
= Velocity at bottom of incline.