Asked by Anonymous
Find ther derivative of the functions.
a. f(x)=(4x-x^2)^100
b. f(x)=(1+2x+x^3)^1/4
a. f(x)=(4x-x^2)^100
b. f(x)=(1+2x+x^3)^1/4
Answers
Answered by
Steve
apply the chain rule. If y = f(u), dy/dx = dy/du * du/dx
a. u = 4x-x^2, y = u^100
b. u = 1+2x+x^3, y = u^1/4
Got it?
a. u = 4x-x^2, y = u^100
b. u = 1+2x+x^3, y = u^1/4
Got it?
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