A stone is thrown horizontally at 30.0m/s from the top of a very tall cliff. Calculate its horizontal position and vertical position at 2s intervals for the first 10.0 s.

Answer 1

come on. This is very straightforward.

horizontal velocity stays constant, 30m/s, so hor. pos. = 30*t

distance fallen = 1/2 at² = 4.9t²