moles soln 1 = M x L = ?
moles soln 2 = M x L = ?
final molarity = total moles/total L. total L will be 60.0 mL = 0.060L.
moles soln 2 = M x L = ?
final molarity = total moles/total L. total L will be 60.0 mL = 0.060L.
First, let's determine the moles of KBr in each initial solution:
For the 36.0 mL of 1.20 M KBr:
moles = volume (in L) x molarity
moles = 0.036 L x 1.20 mol/L
moles = 0.0432 mol
For the 56.0 mL of 0.700 M KBr:
moles = volume (in L) x molarity
moles = 0.056 L x 0.700 mol/L
moles = 0.0392 mol
Next, we need to find the total moles of KBr by summing the moles from both initial solutions:
total moles = moles from the first solution + moles from the second solution
total moles = 0.0432 mol + 0.0392 mol
total moles = 0.0824 mol
Since the total volume of the final solution is 60.0 mL, we need to convert it to liters:
volume (in L) = 60.0 mL รท 1000
volume (in L) = 0.060 L
Finally, we can calculate the molarity of KBr in the final solution:
molarity = total moles รท volume (in L)
molarity = 0.0824 mol รท 0.060 L
molarity โ 1.37 M
Therefore, the molarity of KBr in the final solution is approximately 1.37 M.