Asked by -Untamed-
About rationalizing denominator, is it true that you can't always multiply by the same square root denominator to get a perfect square?
Answers
Answered by
Steve
yes, because (√n)² = n
so, multiplying the root by itself gets rid of the root.
If the denominator is not just a root, but something like √m + n, then you need to multiply by √m - n, since
(√m + n)(√m - n) = m - n²
also, you sometimes have to use
(√m + √n)(√m - √n) = m - n
so, multiplying the root by itself gets rid of the root.
If the denominator is not just a root, but something like √m + n, then you need to multiply by √m - n, since
(√m + n)(√m - n) = m - n²
also, you sometimes have to use
(√m + √n)(√m - √n) = m - n
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.