Asked by Wen
The horsepower (hp) that a shaft can safety transmit varies jointly with its speed (in revolutions per minute, or rpm) and the cube of the diameter. If a shaft of a certain material 2 in in diameter can transmit 36 hp at 75 rpm, what diameter must the shaft have in order to transmit 150 hp at 20 rpm?
Answers
Answered by
Steve
just plug and chug:
hp = k*s*d^3
36 = k * 75 * 2^3
k = 36/(75 * 8) = 36/600
now, for the unknown d
150 = k * 20 * d^3
150 = 36/600 * 20 * d^3
150 * 600/36 * 1/20 = d^3
125 = d^3
hp = k*s*d^3
36 = k * 75 * 2^3
k = 36/(75 * 8) = 36/600
now, for the unknown d
150 = k * 20 * d^3
150 = 36/600 * 20 * d^3
150 * 600/36 * 1/20 = d^3
125 = d^3
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