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Asked by Susana

Find k such that the line is tangent to the graph of the function. Function: f(x)=kã(x)
Line: y=x+4
14 years ago

Answers

Answered by Reiny
I will assume your equation is
f(x) = k√x = k x^(1/2)

then f'(x) = (k/2)x^(-1/2)
but the slope of y = x+4 is 1

so (k/2)x^(-1/2) = 1
k/(2√x) = 1
k = 2√x

then y = 2√x √x = 2x

sub back into y = x+4
2x = x+4
x = 4

so k= 2√4 = 4
14 years ago
Answered by Anonymous
y=2x²√ 2-x
12 years ago

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