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Asked by
Susana
Find k such that the line is tangent to the graph of the function. Function: f(x)=kã(x)
Line: y=x+4
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Answers
Answered by
Reiny
I will assume your equation is
f(x) = k√x = k x^(1/2)
then f'(x) = (k/2)x^(-1/2)
but the slope of y = x+4 is 1
so (k/2)x^(-1/2) = 1
k/(2√x) = 1
k = 2√x
then y = 2√x √x = 2x
sub back into y = x+4
2x = x+4
x = 4
so k= 2√4 = 4
Answered by
Anonymous
y=2x²√ 2-x
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