To calculate the mass of sulfur that combines with 1 gram of iron in both Case 1 and Case 2, we need to use the given percentages by mass of sulfur and iron.
a) Case 1:
In Iron (3) sulphide (Fe2S3), the mass percent of sulfur is 46.3%.
So, we can calculate the mass of sulfur as follows:
Mass of sulfur = 46.3% * 1 gram
= (46.3/100) * 1 gram
= 0.463 grams
b) Case 2:
In Iron (2) sulphide (FeS), the mass percent of sulfur is 36.50%.
Using the same calculation method:
Mass of sulfur = 36.50% * 1 gram
= (36.50/100) * 1 gram
= 0.365 grams
To calculate the ratio of the mass of sulfur that combines with 1 gram of iron in Case 1 (Iron (3) sulphide) to the ratio in Case 2 (Iron (2) sulphide):
Ratio = (Mass of sulfur in Case 1) / (Mass of sulfur in Case 2)
= 0.463 grams / 0.365 grams
≈ 1.27
Therefore, the ratio of the mass of sulfur that combines with 1 gram of iron in Case 1 to the ratio in Case 2 is approximately 1.27.