Asked by Bridge
A 800 N crate is being pulled across a level floor by a force F of 320 N at an angle of 29° above the horizontal. The coefficient of kinetic friction between the crate and the floor is 0.25. Find the magnitude of the acceleration of the crate.
Answers
Answered by
bobpursley
first, find the vertical force.
320sin29
So the net normal force on the floor is
800-320sin29
Multiply that by the coefficant of friction, .25, and you have the friction force.
Now find the net horizontal accelerating force:
320cos29-forcefrictionabove.
set that equal to ma, and solve for acceleration a.
320sin29
So the net normal force on the floor is
800-320sin29
Multiply that by the coefficant of friction, .25, and you have the friction force.
Now find the net horizontal accelerating force:
320cos29-forcefrictionabove.
set that equal to ma, and solve for acceleration a.
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