An experimental rocket car starting from rest reaches a speed of 560 km/h after a straight 450 m run on a level salt flat. Assuming that acceleration is constant, answer the following questios.

(a) What was the time of the run?
Your answer is incorrect. s

(b) What is the magnitude of the acceleration?
m/s2

User Icon for bobpursley bobpursley answered
13 years ago

change km/hr to m/s

distance=avgvelocity*time

450km/hr*1hr/3600sec * 1000m/km=125m/d

time=450m/125m/s= 3.6 seconds.

a= 125/3.6 m/s^2

User Icon for Explain Bot Explain Bot answered
1 year ago

To find the time of the run (a), we need to use the equation of motion for constant acceleration:

v = u + at

Where:
v is the final velocity (560 km/h),
u is the initial velocity (0 km/h, since the car starts from rest),
a is the acceleration,
t is the time.

First, we need to convert the velocities from km/h to m/s:
560 km/h = (560 * 1000) / (60 * 60) = 155.56 m/s
0 km/h = 0 m/s

We can rewrite the equation as:
t = (v - u) / a

Substituting the known values, we have:
t = (155.56 m/s - 0 m/s) / a = 155.56 m/s / a

Therefore, the time of the run (a) is given by the equation 155.56 / a.

To find the magnitude of the acceleration (b), we can rearrange the equation of motion:
v^2 = u^2 + 2as

Where:
v is the final velocity (155.56 m/s),
u is the initial velocity (0 m/s),
a is the acceleration,
s is the displacement (450 m).

Rearranging the equation, we have:
a = (v^2 - u^2) / (2s)

Substituting the known values, we have:
a = (155.56^2 m^2/s^2 - 0^2 m^2/s^2) / (2 * 450 m) = 12160 m^2/s^2 / 900 m

Therefore, the magnitude of the acceleration (b) is given by the equation 12160 / 900 m^2/s^2.

Now you can calculate the time of the run (a) and the magnitude of the acceleration (b) using the derived equations.

User Icon for Step-by-Step Bot Step-by-Step Bot answered
1 year ago

To determine the time of the run and the magnitude of acceleration, we can use the kinematic equation:

v = u + at

where:
v = final velocity = 560 km/h
u = initial velocity = 0 km/h (as the car starts from rest)
a = acceleration
t = time

(a) To find the time of the run:
We need to convert the velocities from km/h to m/s to ensure that the units are consistent.

Given:
v = 560 km/h,
u = 0 km/h.

Converting to m/s:
v = 560 km/h * (1000 m/1 km) * (1 h/3600 s)
= 155.56 m/s

u = 0 km/h * (1000 m/1 km) * (1 h/3600 s)
= 0 m/s

Substituting the values into the equation:

155.56 m/s = 0 m/s + a * t

Simplifying the equation, we have:

155.56 m/s = a * t

(b) To find the magnitude of the acceleration (a):
To find the acceleration, we need to rearrange the equation:

a = (v - u) / t

Substituting the values:

a = (155.56 m/s - 0 m/s) / t

Now we can solve for both t and a.