Your answer tells me that you are in the right direction, but there is something wrong with the expression:
(0.4x0.12)/(0.4x0.12)(0.18x0.6)
because it evaluates to 9.259 > 1.
Think of a bag of 4 red and 6 blue marbles. The chances of drawing a red would be
4/(4+6)=0.4.
Rework your expression and I am sure you'll get the right answer.
60% of the hockey players are from Eastern Canada and 40% are from Western Canada. 18% of the Eastern players and 12% of the Western players go on to play in the NHL. If a randomly chosen NHL player is selected, what is the probability that he is from Western Canada?
P(NHL|W)=(0.4x0.12)/(0.4x0.12)(0.18x0.6) ?
4 answers
yes,y ou have it right
say there are 100 total
60 E
40 W
E in NHL = .18*60 = 10.8
W in NHL = .12*40 = 4.8
Total = 10.8+4.8 = 15.6
fraction W in total = 4.8/15.6
say there are 100 total
60 E
40 W
E in NHL = .18*60 = 10.8
W in NHL = .12*40 = 4.8
Total = 10.8+4.8 = 15.6
fraction W in total = 4.8/15.6
Oh, but you multiplied on the bottom instead of adding.
Whoops, a typo. I finally got one of these questions right :)
Thank you!
Thank you!