6-y
---------
y^2-27-24
well it should simplify to
(6-y)/(y^-1)
which then changes to y(6-y)
which then equals y(6-y)=0
then you set both parts equal to zero and solve for xero
y=0 and/or (6-y)=0
so y=0 or y=6
Did you mean for this problem to be this:
6 - y
-----
y^2 - 2y - 24
If so, factor wherever you can in order to reduce as much as you can.
The denominator as I typed it will factor this way:
(y - 6)(y + 4)
Now we have this:
6 - y
------
(y - 6)(y + 4)
Factor out -1 in the numerator:
-1(y - 6)
---------
(y - 6)(y + 4)
You can cancel out (y - 6) in both the numerator and denominator to reduce.
You are then left with this:
-1
------
(y + 4)
And that's as far as we can go here!
I hope this helps and is what you were asking.