-6(u+5)^2=120
3 answers
-5 + or - 4i squareroot 5
-5 to both sides?
so what about the u?
in the parenthises with the five, what happens to that?
so what about the u?
in the parenthises with the five, what happens to that?
Take the (u+5)^2 and solve (u+5)(u+5)
that gives you -6(u^2-10u-25)=120
then distribute the -6
-6u^2-60u-150= 120 then subtract 120 from both sides
-6u^2-60u-270=0 then divide everythin by -6 giving you
u^2+10u+45=0 then use the quadratic formula
(-b +/- squareroot b^2 -4ac)/2a
then you will get the answer. If you don't know how to use the quadratic formula then let me know.
that gives you -6(u^2-10u-25)=120
then distribute the -6
-6u^2-60u-150= 120 then subtract 120 from both sides
-6u^2-60u-270=0 then divide everythin by -6 giving you
u^2+10u+45=0 then use the quadratic formula
(-b +/- squareroot b^2 -4ac)/2a
then you will get the answer. If you don't know how to use the quadratic formula then let me know.