6. Two lighthouses A and B are 25km apart and A is due West of B. A submarine S is

Question

on a bearing of 1370 from A and on a bearing of 1700 from B. Draw a picture
relevant to the situation, and find the distance of S from A and the distance of S from
B( give all your answers to three significant figures)
How do i solve this useing like sin rule or cosine?.

Answer 1

This question is trigonometry
Angle A = 137°-90°=47°
Angle B = 180°-70°=10°,
10°+90°= 100°
Angle S = 180°-47°-100°=33°
Sine rule
b/sin(Angle B)= s/sin(Angle S )
b/sin100=25/sin33
b= sin100*25/sin33
b= 45.2km, b=AS

a/sin(Angle A)= s/sin(Angle S)
a= sin47*25/sin33
a=33.6km, a=BS
AS=45.2km, BS=33.6km

Answer 2

Sorry Angle B is 180°-170°=10°
10°+90°=100°