(6^5 /6^3) + 7^0 ???
6^2 + 1
37
6 to the power 5 ÷ 6³+7 to the power zero
2 answers
If you mean
(6 to the power 5) ÷ (6³) + (7 to the power zero)
or, losing all the static
6^5 / 6^3 + 7^0
= 6^2 + 1
= 37
You may group otherwise, but the evaluations of the powers will be the same.
(6 to the power 5) ÷ (6³) + (7 to the power zero)
or, losing all the static
6^5 / 6^3 + 7^0
= 6^2 + 1
= 37
You may group otherwise, but the evaluations of the powers will be the same.
3 answers