z = (x -mean)/(sd/sqrt(n))
z = (90.8-88)/(10/sqrt(25))
6) The annual precipitation amounts in a certain mountain range are normally distributed with a mean of 88 inches, and a standard deviation of 10 inches. What is the likelihood that the mean annual precipitation during 25 randomly picked years will be less than 90.8 inches?
2 answers
1.4