6\sqrt{2}\cdot5\sqrt{14}

Answer 1

To find the product of these two terms, we multiply the coefficients (6 and 5) and then multiply the radical terms (sqrt(2) and sqrt(14)).

6 * 5 = 30
sqrt(2) * sqrt(14) = sqrt(28) = 2sqrt(7)

Therefore, the product is:

30 * 2sqrt(7) = 60sqrt(7)