6% of american drivers read the newspaper while driving if 300 drivers are selected at random find the probability that between 15 and 25 say they read while driving

Answer 1

Mean = np = 300 * .06 = ?
Standard deviation = √npq = √(300 * .06 * .94) = ? (Note: q = 1 - p)

Once you have calculated mean and standard deviation, use z-scores to find the probability.

z = (x - mean)/sd

Find two z-scores, using 15 for x and then using 25 for x.

Once you find the z-scores, use a z-table to find the probability between the two scores.

I hope this will help get you started.