To analyze the continuity or discontinuity of the described function, we'll look at the following aspects based on the graph features you've provided:
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First Ray:
- The first ray starts from negative infinity and increases up to the point \((-1, 2.5)\), and it includes this endpoint (as it is noted to be a solid point).
- There is a hole at the point \((-2, 2)\). This indicates that the function is not defined at this point, which creates a gap in the function.
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Isolated Point:
- There is a single isolated point at \((-2, 1)\). Since this point does not connect to the ray, it further contributes to the discontinuity of the function around \(x = -2\).
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Second Ray:
- The second ray starts at an open point \((-1, 3)\). The open point signifies that this value is not included in the function, which indicates another form of discontinuity at \(x = -1\) since the value jumps from \(2.5\) to \(3\) without including \(3\).
Conclusion about Continuity/Discontinuity:
- The function is discontinuous at two significant points:
- At \(x = -2\), due to the hole and the isolated point.
- At \(x = -1\), since there is a jump from \(y = 2.5\) (solid point) to \(y = 3\) (open point).
- Therefore, the overall function is discontinuous at these points, indicating gaps or breaks in the graph.