6 of 116 of 11 Items

Question 1
Emma has $26 for her weekend expenses. She spent $12.81, including tax, on a new book. Additionally, she needs to set aside $10.00 for a lunch outing next week. If stickers cost $0.42 per package, tax included, describe the maximum number of packages (p) Emma can buy.

Which inequality should be used to solve this problem?

(1 point)
Responses

0.42p + 2.81 ≥ 26
0.42p + 2.81 ≥ 26

0.42p + 22.81≤ 26
0.42p + 22.81≤ 26

0.42p + 2.81 ≤ 26
0.42p + 2.81 ≤ 26

0.42p + 22.81≥ 26
0.42p + 22.81≥ 26
Question 2
(1 point)
The maximum number of packages Emma can buy is
.
Skip to navigation

page 1 of 1
Formula keypad has been closed. Press Control + Backslash to open it again.

1 answer

To determine the maximum number of packages of stickers Emma can buy, we first need to analyze her available funds after her expenses.

  1. Total amount available: $26
  2. Amount spent on the book: $12.81
  3. Amount set aside for lunch: $10.00

We can calculate her remaining amount (R) after these expenses:

\[ R = 26 - 12.81 - 10.00 \]

Now let’s compute \(R\):

\[ R = 26 - 12.81 - 10.00 = 26 - 22.81 = 3.19 \]

Now, we need to express her remaining funds in terms of the number of sticker packages (p) she can buy, where each package costs $0.42. The inequality that represents this scenario is:

\[ 0.42p \leq R \]

Substituting \(R\) with $3.19 gives us:

\[ 0.42p \leq 3.19 \]

To answer the questions provided:

  1. The correct inequality to use is \(0.42p + 22.81 \leq 26\), which means 0.42p + 22.81 ≤ 26 (considering this translates her total budget after subtracting known expenses).

  2. The maximum number of packages Emma can buy can be calculated by solving:

\[ p \leq \frac{3.19}{0.42} \]

Calculating:

\[ p \leq 7.5952 \]

Since she can only buy whole packages, we take the maximum whole number, which is \(p = 7\).

Thus, the answers are:

  1. The inequality is 0.42p + 22.81 ≤ 26.
  2. The maximum number of packages Emma can buy is 7.