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Question

Question 1
A school class is selling cookies for a fundraiser. The class has made 120 cookies to sell, and the supplies to make the cookies cost $22. The class wants to make at least $50 from selling cookies.

Which inequality should be used to determine the possible prices (p) the class can sell the cookies for to reach its goal?

(1 point)
Responses

120p−22≥50
120 p minus 22 is greater than or equal to 50

120p−22>50
120 p minus 22 is greater than 50

120p−22≤50
120 p minus 22 is less than or equal to 50

120p−22<50
120p−22<50
Question 2
(1 point)
The class should sell each cookie for
greater than
at most
exactly
at least
least than
$0.60.
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Answer 1

To determine the appropriate inequality for the scenario presented, let's break it down:

1. Total cookies: 120
2. Cost of supplies: $22
3. Goal for profit: at least $50

The total income from selling the cookies is given by the price per cookie (p) multiplied by the number of cookies, which is 120p. To find the profit, we subtract the cost of supplies from the total income:

Profit = Total Income - Cost = 120p - 22.

To meet the goal of making at least $50 in profit, the inequality becomes:

120p - 22 ≥ 50.

Thus, the correct response for Question 1 is:

120p - 22 ≥ 50.

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For Question 2, we need to solve the inequality to find the minimum price per cookie (p) the class should sell the cookies for:

Starting from:

120p - 22 ≥ 50

1. Add 22 to both sides:

120p ≥ 72

2. Divide both sides by 120:

p ≥ 72/120

3. Simplifying 72/120 yields:

p ≥ 0.60.

Therefore, the class should sell each cookie for at least $0.60.