Question

6 of 116 of 11 Items Question 1 A school class is selling cookies for a fundraiser. The class has made 120 cookies to sell, and the supplies to make the cookies cost $22. The class wants to make at least $50 from selling cookies. Which inequality should be used to determine the possible prices (p) the class can sell the cookies for to reach its goal? (1 point) Responses 120p−22<50 120p−22<50 120p−22≥50 120 p minus 22 is greater than or equal to 50 120p−22≤50 120 p minus 22 is less than or equal to 50 120p−22>50 120 p minus 22 is greater than 50 Question 2 (1 point) The class should sell each cookie for $0.60.

Answer 1

To determine the inequality that represents the situation, we need to consider the total revenue from selling cookies and the minimum profit the class wants to achieve.

1. The total revenue from selling the cookies is given by \(120p\), where \(p\) is the price per cookie.
2. The total cost of making the cookies is $22.
3. The class wants to make at least $50 profit from selling the cookies.

The profit can be represented as the total revenue minus the total cost:

\[ \text{Profit} = \text{Total Revenue} - \text{Total Cost} \]

Substituting in the values we have:

\[ \text{Profit} = 120p - 22 \]

To earn at least $50 in profit, we set up the inequality:

\[ 120p - 22 \geq 50 \]

So the correct inequality to determine the possible prices \(p\) is:

120p - 22 ≥ 50

For Question 2, if the class sells each cookie for $0.60, we can check if this meets the goal.

1. Calculate the total revenue if the price per cookie is $0.60:

\[ 120p = 120 \times 0.60 = 72 \]

2. Calculate the profit:

\[ \text{Profit} = 72 - 22 = 50 \]

Since the profit of $50 meets the goal of at least $50, the price of $0.60 per cookie is acceptable.