6. If 3(log2 a+log2 3)=1/9. then a is equal to:-

Answer 1

To solve this equation, let's simplify the expression on the left side first:

3(log2 a + log2 3) = 1/9

Using the logarithm property log_b(x) + log_b(y) = log_b(xy), we can rewrite the equation as:

log2 (a * 3^3) = 1/9

Simplifying further, we have:

log2 (27a) = 1/9

Next, we rewrite the equation in exponential form:

2^(1/9) = 27a

Taking the 9th root of 2, we get:

27^(1/9) = a

Since 27^(1/9) is equal to 3, the value of a is:

a = 3