First, let's rewrite the equation of the line in slope-intercept form (y = mx + b), where m is the slope:
2y = -6x + 8
y = (-6/2)x + 8/2
y = -3x + 4
The slope of the given line is -3.
In order to find the slope of a line perpendicular to this one, we need to calculate the negative reciprocal of the slope of the given line.
The negative reciprocal of -3 is 1/3.
Therefore, the slope of a line perpendicular to 2y = -6x + 8 is 1/3.
6.
Find the slope of a line perpendicular to 2y= - 6x + 8
1 answer