Kinetic energy of moving vehicle
=(1/2)mv²
=(1/2)1580*15²
=177750 J
Work done by braking force, F
=F.d
=50F
Equate energies:
50F=177750J
F=177750/50 N
=3555N
6. A 1580 kg car is traveling with a speed of 15.0 m/s. What is the magnitude of the horizontal net force that is required to bring the car to a halt in a distance of 50.0 m?
1 answer