(-6.8) x (3.4) = -23.12
To multiply -2 ⅕ by -8, we need to convert the mixed number to an improper fraction. -2 ⅕ is equal to -11/5. Then, we multiply -11/5 by -8 to get 88/5, which simplifies to 17 ⅗.
Lake Placid is 40 feet deep. Since Lake Acid is 120 feet below the surface, Lake Placid, which is ⅓ as deep, would be 120/3 = 40 feet deep.
To find the quotient of 8 ¼ divided by 2 ½, we convert the mixed numbers to improper fractions. 8 ¼ is equal to 33/4 and 2 ½ is equal to 5/2. Then, we divide 33/4 by 5/2 to get 33/4 ÷ 5/2 = 33/4 x 2/5 = 66/20, which simplifies to 3 1/10.
The change in water in 1 minute is 24/6 = 4 gallons.
(-6.8) x (3.4) = ?
Multiply -2 ⅕ by -8. Write as simplifed mixed number
Lake Acid has a depth of 120ft below the surfacel. Lake Placid is ⅓ as deep. How deep is Lake Placid? Use appropriate integer to account for elevation.
Find the quotient of 8 ¼ and 2 ½. Simplified fraction
A tank holds 500 gallons of water. It drains 24 gallons of water in 6 minutes. What is the change in water in 1 minute? (remember integer representation is necessary) write in 3 sentence
3 answers
(-6.8) x (3.4) = ?
Multiply -2 ⅕ by -8. Write as simplifed mixed number
Lake Acid has a depth of 120ft below the surfacel. Lake Placid is ⅓ as deep. How deep is Lake Placid? Use appropriate integer to account for elevation.
Find the quotient of 8 ¼ and 2 ½. Simplified fraction
A tank holds 500 gallons of water. It drains 24 gallons of water in 6 minutes. What is the change in water in 1 minute? (remember integer representation is necessary) write in 4 to 5 sentence
Multiply -2 ⅕ by -8. Write as simplifed mixed number
Lake Acid has a depth of 120ft below the surfacel. Lake Placid is ⅓ as deep. How deep is Lake Placid? Use appropriate integer to account for elevation.
Find the quotient of 8 ¼ and 2 ½. Simplified fraction
A tank holds 500 gallons of water. It drains 24 gallons of water in 6 minutes. What is the change in water in 1 minute? (remember integer representation is necessary) write in 4 to 5 sentence
(-6.8) x (3.4) = -23.12
To multiply -2 ⅕ by -8, we need to convert the mixed number to an improper fraction. -2 ⅕ is equal to -11/5. Then, we multiply -11/5 by -8 to get 88/5, which simplifies to 17 ⅗.
Lake Placid is 40 feet deep. Since Lake Acid is 120 feet below the surface, Lake Placid, which is ⅓ as deep, would be 120/3 = 40 feet deep.
To find the quotient of 8 ¼ divided by 2 ½, we convert the mixed numbers to improper fractions. 8 ¼ is equal to 33/4 and 2 ½ is equal to 5/2. Then, we divide 33/4 by 5/2 to get 33/4 ÷ 5/2 = 33/4 x 2/5 = 66/20, which simplifies to 3 1/10.
The tank drains 24 gallons of water in 6 minutes, so in 1 minute it drains 24/6 = 4 gallons. The change in water in 1 minute is -4 gallons, as it is being drained and the integer representation accounts for the decrease in water level.
To multiply -2 ⅕ by -8, we need to convert the mixed number to an improper fraction. -2 ⅕ is equal to -11/5. Then, we multiply -11/5 by -8 to get 88/5, which simplifies to 17 ⅗.
Lake Placid is 40 feet deep. Since Lake Acid is 120 feet below the surface, Lake Placid, which is ⅓ as deep, would be 120/3 = 40 feet deep.
To find the quotient of 8 ¼ divided by 2 ½, we convert the mixed numbers to improper fractions. 8 ¼ is equal to 33/4 and 2 ½ is equal to 5/2. Then, we divide 33/4 by 5/2 to get 33/4 ÷ 5/2 = 33/4 x 2/5 = 66/20, which simplifies to 3 1/10.
The tank drains 24 gallons of water in 6 minutes, so in 1 minute it drains 24/6 = 4 gallons. The change in water in 1 minute is -4 gallons, as it is being drained and the integer representation accounts for the decrease in water level.