(6-3w)(-w2) the two in the second set is a exponent. How do I solve this?

Answer 1

(6-3w)(-W^2).
We have an algebraic expression that's
already factored. So what is the question? Did you mean (6-3W)(-W^2)=0 ?
If so,

6-3W = 0
-3W = -6
W = 2

-W^2 = 0
W^2 = 0
W = 0

Solution Set: W = 0, and 2.