Except that indeed 8 - 6 - 2 = 0
I have no idea what you mean.
Are x1 and x2 vectors multiplied by square matrices or what?
6 2 6
Let u = 4 , v = 2 , w = 2
5 3 1
Show that 2u - 3v - w = 0. Use that fact to find x1 and x2 that satisfy the equation
6 2 6
4 2 {x1} = 2
5 3 {x2} 1
5 answers
u=6
4
5
v=2
2
3
w=6
2
1
show that 2u - 3v - w = 0
Sorry!! I hope this makes a bit more sense...Can we try to do this step by step so I can understand it better?
4
5
v=2
2
3
w=6
2
1
show that 2u - 3v - w = 0
Sorry!! I hope this makes a bit more sense...Can we try to do this step by step so I can understand it better?
Then after this, use that fact to find x1 and x2 that satisfies the equation:
6 2 6
4 2 2
5 3 {x1 and x2} = 1
6 2 6
4 2 2
5 3 {x1 and x2} = 1
just add them up:
2u-3v-w =
12-6-6
8-6-2
10-9-1
=
0
0
0
2u-3v-w =
12-6-6
8-6-2
10-9-1
=
0
0
0
The 6
2
1
is supposed to be on the right hand side of the equal sign. I am so sorry again!!!
2
1
is supposed to be on the right hand side of the equal sign. I am so sorry again!!!