How about this pattern
term(1) = 6 = 3(2^1)
term(2) = 12 = 3(2^2)
term(3) = 24 = 3(2^3)
term(4) = 48 = 3(2^4)
....
term(23) = .... = 3(2^23)
term(n) = .....
6,12,24,48,96...... How can you define the nth term
1 answer