To solve the given system of equations, we can use the method of substitution or elimination.
We'll use the method of elimination:
First, let's multiply the second equation by 5 to make the coefficients of x in both equations the same:
- x + 3y = 22
Multiplying both sides by 5:
-5x + 15y = 110
Now, we can add the two equations:
5x - 4y = -44
-5x + 15y = 110
Adding the two equations together:
(-5x + 5x) + (-4y + 15y) = -44 + 110
0x + 11y = 66
11y = 66
Now, we can solve for y by dividing both sides by 11:
11y/11 = 66/11
y = 6
Now, substitute the value of y back into one of the original equations to solve for x:
- x + 3(6) = 22
- x + 18 = 22
- x = 22 - 18
- x = 4
Therefore, the solution to the given system of equations is x = 4 and y = 6.
5x - 4y = -44
- x + 3y = 22
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