NaOH + HCl ==> NaCl + H2O
mols NaOH = M x L = 1.0 x 0.5 = 0.5
mols HCl = M x L = 0.025 x 2 = 0.05
So HCl is the limiting reagent.
q = mass H2O x specific heat H2O x (Tfinal-Tinitial)
Find q. That is q/0.05 mol H2O.
Convert to kJ/mol
This is the right way to do it but I don't think it gives the correct answer. Check the problem to be sure the numbers are right. Could that be 1.52 C and not 15.2?
5oocm3 of 1.0 mol dm3 of sodium hydroxide solution at room temperature was placed in a styrofoam cup and 25cm3 of 2.0 mol-dm3 of hydrochloric acid was added at the same temperature.The temperature rose by 15.2 degrees celsius. Calculate the heat of neurtralization
1 answer
1 answer