5m-7=3, what is m?

Answer 1

To solve the equation \( 5m - 7 = 3 \), you can follow these steps:

1. Add 7 to both sides of the equation: \[ 5m - 7 + 7 = 3 + 7 \] \[ 5m = 10 \]

2. Divide both sides by 5: \[ m = \frac{10}{5} \] \[ m = 2 \]

So, the value of \( m \) is \( 2 \).

Answer 2

Sarah is planning to buy some books. Each book (b) costs $15. How many books can Sarah purchase if she has saved $60?
A 15 + 60 = b
B 60b = 15
C 15 + b = 60
D 15b = 60

Answer 3

To find out how many books \( b \) Sarah can buy with her savings of $60, we need to set up an equation based on the cost of the books. Each book costs $15, and she has $60 saved.

We can express this situation with the equation:

\[ 15b = 60 \]

This means that the total cost of \( b \) books at $15 each should equal her total savings of $60.

So the correct choice from the options provided is:

D) \( 15b = 60 \)

Now, to find the number of books Sarah can buy, we can solve for \( b \):

1. Divide both sides by 15: \[ b = \frac{60}{15} = 4 \]

Thus, Sarah can purchase 4 books.

Answer 4

pick one

Answer 5

The correct choice is:

D) \( 15b = 60 \)

Answer 6

Spencer prepaid a 12-month membership to Power Score Gym. He received a one-time discount of $35 for prepaying. Spencer paid a total of $205.
Which equation can Spencer use to find m, the regular cost per month?
A 12m - 35 = 205
B 35m - 12 = 205
C 35(m - 12) = 205
D 12(m - 35) = 205

Answer 7

To find the regular cost per month \( m \) for Spencer's gym membership, we need to account for the total cost he paid after applying the one-time discount.

Spencer prepaid for 12 months, which would normally cost \( 12m \) (where \( m \) is the regular monthly cost). Since he received a discount of $35, the equation would be:

\[ 12m - 35 = 205 \]

This represents the total regular cost for 12 months minus the discount equaling the total amount he actually paid.

Therefore, the correct choice is:

A) \( 12m - 35 = 205 \).

Answer 8

2/3n-6=-8?

Answer 9

To solve the equation \( \frac{2}{3}n - 6 = -8 \), follow these steps:

1. Add 6 to both sides to isolate the term with \( n \): \[ \frac{2}{3}n - 6 + 6 = -8 + 6 \] \[ \frac{2}{3}n = -2 \]

2. Multiply both sides by the reciprocal of \( \frac{2}{3} \) (which is \( \frac{3}{2} \)) to solve for \( n \): \[ n = -2 \times \frac{3}{2} \] \[ n = -3 \]

So, the solution is \( n = -3 \).