5F2(g) + 2NH3(g) ==> N2F4(g) + 6HF(g) If you have 225 g F2, how many grams of N2F4 will be produced

Answer 1

The reaction of fluorine with ammonia produces dinitrogen tetrafluoride and hydrogen fluoride.
5F2 (g) + 2NH3 (g) → N2F4 (g) + 6HF(g)
A. If you have 66.6 g NH3, how many grams of F2 are required for complete reaction?
B. How many grams of NH3 are required to produce 4.65 g HF?
C. How many grams of N2F4 can be produced from 225 g F2?
A. 372 g F2
B. 1.32 g NH3
C. 123 g N2F4

Answer 2

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