I think something's wrong here. sqrt(25-x^2) is one side of the triangle, arccos(x/5) is the angle opposite that side.
That will not simplify in any useful way.
Let f(x)= (sqrt(25−x^2))+5 arccos (x/5).
Then f(x) can be written in the simplified form − [(x+c)/mx+n)]^p.
What are the values of c,m,n and p?
Please tell me how to do this question.
Thanks
1 answer