Asked by Haile
Express the repeating decimal 0.513 (the 13 is repeating) as a fraction in lowest terms using the infinite geometric series method.
Answers
Answered by
bobpursley
.513= .510+ 3/1000 + 3.10000+ 3/1E5 +3/1E6+ ...
notice that this is ...
= .510+ 3/1000 (1+ (1/10)+ (1/10)^3+..)
sum of
= .510 + 3/1000(1/.9)=+510/1000+3/900
= (510*9+300)/9000 check that
= (4590+ 300) /9000 = 4890/9000=489/900
notice that this is ...
= .510+ 3/1000 (1+ (1/10)+ (1/10)^3+..)
sum of
= .510 + 3/1000(1/.9)=+510/1000+3/900
= (510*9+300)/9000 check that
= (4590+ 300) /9000 = 4890/9000=489/900
Answered by
Haile
the 1 and the there are repeating so it's .513131313131313... and 489/900 isn't giving me that. could you explain it again?
Answered by
mia
what 9,000=900x_
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