Asked by Anonymous
maria rented the same car twice in one month. She paid $180 the first rime for 3 days and she drove a total of 150 km. The next time, she also paid $180 and had the vehicle for only 2 day, but traveled 400 km. A. What was the cost per day. B. What was the cost per kilometer
Answers
Answered by
Helper
Say, cost per day = D
Say, cost per km = k
3D + 150k = 180
2D + 400k = 180
Multiply the first equation by 2 and the second by 3:
6D + 300k = 360
6D + 1200k = 540
Subtract the first equation from the second:
900k = 180
Divide both sides by 900:
k = 0.2
2D + 400k = 180
2D + 400(0.2) = 180
2D + 80 = 180
Subtract 80 from both sides:
2D = 100
D = 50
The cost per day is $50 and the cost per km is $0.20
Say, cost per km = k
3D + 150k = 180
2D + 400k = 180
Multiply the first equation by 2 and the second by 3:
6D + 300k = 360
6D + 1200k = 540
Subtract the first equation from the second:
900k = 180
Divide both sides by 900:
k = 0.2
2D + 400k = 180
2D + 400(0.2) = 180
2D + 80 = 180
Subtract 80 from both sides:
2D = 100
D = 50
The cost per day is $50 and the cost per km is $0.20
Answered by
Courtney
part 1
Describe the graphs of the functions f(x) = 2^x – 1 and g(x) = –2^x – 1.
Part 2
Compare and contrast the domain and range of f(x) and g(x).
Describe the graphs of the functions f(x) = 2^x – 1 and g(x) = –2^x – 1.
Part 2
Compare and contrast the domain and range of f(x) and g(x).
Answered by
Ismail
thank you
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