Asked by allyson
A golf ball with an initial angle of 35° lands exactly 218 m down the range on a level course.
(a) Neglecting air friction, what initial speed would achieve this result?
m/s
(b) Using the speed determined in item (a), find the maximum height reached by the ball.
m
(a) Neglecting air friction, what initial speed would achieve this result?
m/s
(b) Using the speed determined in item (a), find the maximum height reached by the ball.
m
Answers
Answered by
bobpursley
Vertical equation
hf=hi+Vi*sin35*time - 4.9 time^2
0=t(Vi*sin35 -4.9t) so t is
t=Vi*sin35/4.9
Horizontal equation. Put that time t in to this equation, and solve for Vi.
218=vi*cos35*t
hf=hi+Vi*sin35*time - 4.9 time^2
0=t(Vi*sin35 -4.9t) so t is
t=Vi*sin35/4.9
Horizontal equation. Put that time t in to this equation, and solve for Vi.
218=vi*cos35*t
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