Asked by Blue
log4x^4 + log4^2 = 3
Solve the logarithmic equation.
Solve the logarithmic equation.
Answers
Answered by
Steve
log4x^4 = log4 + 4logx
log4^2 = 2log4
log4 + 4logx + 2log4 = 3
3log4 + 4logx = 3
4logx = 3(1-log4)
Now, if we're dealing with base 10, 1 = log10, so 1-log4 = log(10/4) = log(5/2)
4 logx = 3log(5/2)
logx = 3/4 log(5/2)
x = 10^(3/4) * l0^(log 5/2)
x = 10^3/4 * 5/2
x = 5/2 10^(3/4)
x = 5/2 ∜1000
log4^2 = 2log4
log4 + 4logx + 2log4 = 3
3log4 + 4logx = 3
4logx = 3(1-log4)
Now, if we're dealing with base 10, 1 = log10, so 1-log4 = log(10/4) = log(5/2)
4 logx = 3log(5/2)
logx = 3/4 log(5/2)
x = 10^(3/4) * l0^(log 5/2)
x = 10^3/4 * 5/2
x = 5/2 10^(3/4)
x = 5/2 ∜1000
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